If a ball is thrown at a velocity of 45 ,m/s | vedclass

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(A) For the ball,we have initial velocity $u = 45 \,m/s$ and acceleration $g = -10 \,m/s^2$.Using the kinematic equation $v^2 - u^2 = 2gh$,we get:$v^2

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(A) For the ball,we have initial velocity $u = 45 \,m/s$ and acceleration $g = -10 \,m/s^2$.Using the kinematic equation $v^2 - u^2 = 2gh$,we get:$v^2 = u^2 + 2gh$$v^2 = (45)^2 + 2(-10)h$$v^2 = 2025 - 20h$$v = \sqrt{2025 - 20h}$This equation represents a parabola opening towards the left in the $v-h$ plane. At $h = 0$,$v = 45 \,m/s$.At $v = 0$,$h = 2025 / 20 = 101.25 \,m \approx 101 \,m$.Since the relationship is $v^2 = 2025 - 20h$,the graph of $v$ versus $h$ is a part of a parabola. Among the given options,the curve in option $(A)$ correctly represents this parabolic relationship where velocity decreases as height increases.

If a ball is thrown at a velocity of $45 \,m/s$ in the vertical upward direction,what would be the velocity profile as a function of height? (Assume $g = 10 \,m/s^2$)

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