If pK_b for fluoride ion (F^-) at 25,^{circ}C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given $pK_b = 10.83$ for $F^-$. The base dissociation constant $K_b = 10^{-pK_b} = 10^{-10.83} = 1.479 	imes 10^{-11} \approx 1.48 	imes 10^{-11

Vedclass · Accepted Answer

$6.75 	imes 10^{-4}$

Vedclass · Answer

(C) Given $pK_b = 10.83$ for $F^-$. The base dissociation constant $K_b = 10^{-pK_b} = 10^{-10.83} = 1.479 	imes 10^{-11} \approx 1.48 	imes 10^{-11}$. At $25\,^{\circ}C$,the ionic product of water $K_w = 10^{-14}$. The relationship between $K_a$ and $K_b$ for a conjugate acid-base pair is $K_a 	imes K_b = K_w$. Therefore,$K_a = \frac{K_w}{K_b} = \frac{10^{-14}}{1.48 	imes 10^{-11}} = 6.756 	imes 10^{-4} \approx 6.75 	imes 10^{-4}$.

If $pK_b$ for fluoride ion $(F^-)$ at $25\,^{\circ}C$ is $10.83$,the ionisation constant $(K_a)$ of hydrofluoric acid $(HF)$ in water at this temperature is:

Similar Questions

Which of the following mixing of $1 \ M$ base and $1 \ M$ acid leads to the largest increase in temperature?

According to the Lewis concept,an acid is a substance which

The number of species among the following that can act both as Bronsted acids and bases is $HCl, ClO_4^{-}, OH^{-}, H^{+}, H_2O, HSO_4^{-}, SO_4^{2-}, H_2SO_4, Cl^{-}$.

The strongest conjugate base is:

The self-ionization constant of $NH_3$ is $........... $.

Vedclass Test Series

Exam Paper Generator

Online Exam Module