If $97.52$ is divided by $2.54$,the correct result in terms of significant figures is

If $N_A, N_B$,and $N_C$ are the number of significant figures in $A=0.001204 \ m$,$B=43120000 \ m$,and $C=1.200 \ m$ respectively,then:

Match the numbers in Column-$I$ with the number of significant figures in Column-$II$.

Column-$I$	Column-$II$
$(1)$ $2.85 \times 10^{26} \ kg$	$(a)$ $1$
$(2)$ $0.009 \ m^2$	$(b)$ $2$
$(3)$ $0.060 \ s$	$(c)$ $3$

Which is the best method to determine significant numbers?

Match List-$I$ with List-$II$.

List-$I$ (Number)	List-$II$ (Significant figures)
$A. 1001$	$I. 3$
$B. 010.1$	$II. 4$
$C. 100.100$	$III. 5$
$D. 0.0010010$	$IV. 6$

Choose the correct answer from the options given below:

$A$ substance of mass $49.53 \ g$ occupies $1.5 \ cm^3$ of volume. The density of the substance (in $g \ cm^{-3}$) with the correct number of significant figures is: