If PQ and PR are the two sides of a triangle, | vedclass

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(D) Let the lengths of the sides $PQ$ and $PR$ be $a$ and $b$ respectively.The area $\Delta$ of the triangle is given by the formula:$\Delta = \frac{1

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$\pi/2$

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(D) Let the lengths of the sides $PQ$ and $PR$ be $a$ and $b$ respectively.The area $\Delta$ of the triangle is given by the formula:$\Delta = \frac{1}{2} ab \sin 	heta$,where $	heta$ is the angle between the sides $PQ$ and $PR$.Since $a$ and $b$ are constant lengths,the area $\Delta$ is directly proportional to $\sin 	heta$.The area is maximized when $\sin 	heta$ attains its maximum value.We know that the maximum value of $\sin 	heta$ is $1$,which occurs when $	heta = \frac{\pi}{2}$.Therefore,the angle between the sides that gives the maximum area is $\frac{\pi}{2}$.

If $PQ$ and $PR$ are the two sides of a triangle,then the angle between them which gives the maximum area of the triangle is

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