If $\vec{a}$ and $\vec{b}$ are two vectors such that $|\vec{a}|=3, |\vec{b}|=4, |\vec{a}+\vec{b}|=\sqrt{37}, |\vec{a}-\vec{b}|=k$ and the angle between $\vec{a}$ and $\vec{b}$ is $\theta$,then find the value of $\frac{4}{13}(k \sin \theta)^2$.

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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