If $x$ and $y$ represent the number of arrangements of the letters of the word $ATRAPATRAM$ such that $(i)$ all $A$'s are together and $(ii)$ no two $A$'s are together respectively,then $x+y$ is equal to:

  • A
    $\frac{10!}{4!2!2!}$
  • B
    $\frac{7! \times 15}{2!2!4!}$
  • C
    $\frac{6!}{2!2!} \times 42$
  • D
    $\frac{7!}{2!2!} + \frac{6! \cdot ^7P_4}{2!2!}$

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