If vec{a} = t vec{b} where t

Question

(D) Given $\vec{a} = t \vec{b}$ where $t < 0$ is a scalar. Since $t$ is negative,the vectors $\vec{a}$ and $\vec{b}$ must point in opposite directions

Vedclass · Accepted Answer

$\vec{a}, \vec{b}$ are unlike vectors and either $|\vec{a}| \geq |\vec{b}|$ or $|\vec{a}| < |\vec{b}|$

Vedclass · Answer

(D) Given $\vec{a} = t \vec{b}$ where $t Since $t$ is negative,the vectors $\vec{a}$ and $\vec{b}$ must point in opposite directions,which means they are unlike vectors. Taking the modulus on both sides: $|\vec{a}| = |t \vec{b}| = |t| |\vec{b}|$. Since $t If $|t| > 1$,then $|\vec{a}| > |\vec{b}|$. If $|t| = 1$,then $|\vec{a}| = |\vec{b}|$. If $0 Therefore,$\vec{a}$ and $\vec{b}$ are unlike vectors,and the relationship between their magnitudes depends on the value of $|t|$,which can be either $|\vec{a}| \geq |\vec{b}|$ or $|\vec{a}| < |\vec{b}|$.

If $\vec{a} = t \vec{b}$ where $t < 0$ is a scalar,then

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