If $\lim _{x \rightarrow \infty} y(x)=\frac{\pi}{2}$,then the solution of $x^3 \sin y \frac{d y}{d x}=2$ is $\cos y=$

  • A
    $\frac{3}{x^2}$
  • B
    $\frac{1}{x}$
  • C
    $\frac{1}{x^2}$
  • D
    $\frac{2}{x^3}$

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