If $f(x)=(x-1)(x-2)(x-3)$ for $x \in[0,4]$,then the value of $c \in(0,4)$ satisfying Lagrange's mean value theorem is:

  • A
    $3 \pm \frac{\sqrt{2}}{3}$
  • B
    $2 \pm \frac{2 \sqrt{3}}{3}$
  • C
    $2 \pm \frac{\sqrt{3}}{2}$
  • D
    $3 \pm \frac{\sqrt{3}}{3}$

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