If $f(x)=x^3+p x^2+q x$ is defined on $[0,2]$ such that $f(0)=f(2)$ and $f^{\prime}\left(1+\frac{1}{\sqrt{3}}\right)=0$,then $p^2+q^2=$

  • A
    $13$
  • B
    $5$
  • C
    $2+\frac{1}{\sqrt{3}}$
  • D
    $1$

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