If $x \in \mathbb{R}$,then the range of $\frac{x}{x^2-5x+9}$ is
- A$\left(-\frac{1}{11}, 1\right)$
- B$\left(-\infty, -\frac{1}{11}\right) \cup (1, \infty)$
- C$\left[-\frac{1}{11}, 1\right]$
- D$\left[-1, \frac{1}{11}\right]$
Explore More
Similar Questions
The domain of the function $f(x) = \sin^{-1}\left[\log_4\left(\frac{x}{4}\right)\right] + \sqrt{17x - x^2 - 16}$ is
The domain of the function $f(x) = \sqrt{\log_{0.5} x!}$ is
$A$ real-valued function $f: A \rightarrow B$ defined by $f(x) = \frac{4-x^2}{4+x^2}$ for all $x \in A$ is a bijection. If $-4 \in A$,then $A \cap B =$
$A$ real valued function $f(x) = |x^2 - 3x + 2| + 2x - 3$ is defined on $[-2, 1]$. If $m$ and $M$ are absolute minimum and absolute maximum values of $f$ respectively,then $M - 4m =$
Find the range of the following function:
$f(x) = x$,where $x$ is a real number.
$f(x) = x$,where $x$ is a real number.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo