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(C) Given that $A$ is a square matrix of order $n = 3$. We know the property of the adjoint of a matrix: $|\operatorname{adj}(\operatorname{adj} M)| =

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$|A|^8$

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(C) Given that $A$ is a square matrix of order $n = 3$. We know the property of the adjoint of a matrix: $|\operatorname{adj}(\operatorname{adj} M)| = |M|^{(n-1)^2}$. Here,we need to find $|\operatorname{adj}(\operatorname{adj} A^2)|$. Let $M = A^2$. Then,$|\operatorname{adj}(\operatorname{adj} A^2)| = |A^2|^{(3-1)^2}$. Since $(3-1)^2 = 2^2 = 4$,we have $|\operatorname{adj}(\operatorname{adj} A^2)| = |A^2|^4$. Using the property $|A^k| = |A|^k$,we get $|A^2|^4 = (|A|^2)^4 = |A|^8$. Therefore,the correct option is $|A|^8$.

If $A$ is a square matrix of order $3$,then $|\operatorname{adj}(\operatorname{adj} A^2)|$ is equal to

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