If cos theta = frac{-3}{5} and theta does not | vedclass

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(C) Given $\cos 	heta = \frac{-3}{5}$.Since $\cos 	heta < 0$ and $	heta$ is not in the second quadrant,$	heta$ must lie in the third quadrant.Thus

Vedclass · Accepted Answer

$-2$

Vedclass · Answer

(C) Given $\cos 	heta = \frac{-3}{5}$.Since $\cos 	heta Thus,$\pi Dividing by $2$,we get $\frac{\pi}{2} This implies $\frac{	heta}{2}$ lies in the second quadrant,where $	an \frac{	heta}{2}$ is negative.Using the formula $	an \frac{	heta}{2} = \pm \sqrt{\frac{1 - \cos 	heta}{1 + \cos 	heta}}$,we have:$	an \frac{	heta}{2} = - \sqrt{\frac{1 - (\frac{-3}{5})}{1 + (\frac{-3}{5})}}$$= - \sqrt{\frac{1 + \frac{3}{5}}{1 - \frac{3}{5}}}$$= - \sqrt{\frac{8/5}{2/5}}$$= - \sqrt{4} = -2$.

If $\cos \theta = \frac{-3}{5}$ and $\theta$ does not lie in the second quadrant,then $\tan \frac{\theta}{2} = $

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