If $\theta = \frac{\pi}{6}$ and $x = \log \left[ \cot \left( \frac{\pi}{4} + \theta \right) \right]$,then $\sinh(x) =$

  • A
    $\sqrt{3}$
  • B
    $\frac{1}{\sqrt{3}}$
  • C
    $-\sqrt{3}$
  • D
    $-\frac{1}{\sqrt{3}}$

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Similar Questions

Match the items of List-$I$ to the items of List-$II$:
List-$I$List-$II$
$A$. The period of $\sin^2 x$ is$I$. $\frac{2\pi}{3}$
$B$. Maximum value of $\frac{\pi}{3}(\sqrt{3}\cos 3x + \sin 3x)$$II$. $12\pi$
$C$. The period of $\sin \frac{x}{3} + \cos \frac{x}{2}$ is$III$. $\frac{\pi}{2}$
$D$. Intersection points of $y=|\sin x|$ and $y=1$ in $(0, \pi)$$IV$. $\frac{3\pi}{2}$
$V$. $\pi$

Evaluate the expression: $\left(1+\cos \frac{\pi}{8}\right)\left(1+\cos \frac{2 \pi}{8}\right)\left(1+\cos \frac{3 \pi}{8}\right)\left(1+\cos \frac{4 \pi}{8}\right)\left(1+\cos \frac{5 \pi}{8}\right)\left(1+\cos \frac{6 \pi}{8}\right)\left(1+\cos \frac{7 \pi}{8}\right)$

If $\alpha = \frac{\sin^3 x}{\cos^2 x}$,$\beta = \frac{\cos^3 x}{\sin^2 x}$ and $\sin x + \cos x = k$,then $\alpha \sin x + \beta \cos x + 3 = $

If $\sin x + \sin y = \frac{7}{5}$ and $\cos x + \cos y = \frac{1}{5}$,then $\sin(x + y)$ equals

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