If $R$ is the radius of the circumcircle of the $\Delta ABC$ and $\Delta$ is its area,then
- A$R = \frac{a + b + c}{\Delta}$
- B$R = \frac{a + b + c}{4\Delta}$
- C$R = \frac{abc}{4\Delta}$
- D$R = \frac{abc}{\Delta}$
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Similar Questions
In $\triangle ABC$,find the value of $r_1+r_2+r_3$.
In a $\triangle ABC$,which of the following formulae are correct?
$I. r = 4R \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2}$
$II. r_1 = (s-a) \tan \frac{A}{2}$
$III. r_3 = \frac{\Delta}{s-c}$
$I. r = 4R \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2}$
$II. r_1 = (s-a) \tan \frac{A}{2}$
$III. r_3 = \frac{\Delta}{s-c}$
In a triangle $ABC$,with usual notation,if $a=12, b=16, c=20$,then the ratio of the exradii of the triangle opposite to the angles in the order $\angle C, \angle B, \angle A$ is
In a triangle $ABC$,if $r r_2 = r_1 r_3$,then $\cos 2B =$
If $ABC$ is an isosceles triangle with base $BC$,then $rr_1=$
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