If $a = 9, b = 8$ and $c = x$ satisfies $3 \cos C = 2$,then

  • A
    $x = 5$
  • B
    $x = 6$
  • C
    $x = 4$
  • D
    $x = 7$

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In any $\triangle ABC$,$a(b \cos C - c \cos B)$ equals

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