If $f(x) = \begin{cases} \frac{x^2 - (a+2)x + a}{x-2} & x \neq 2 \\ 2 & x = 2 \end{cases}$ is continuous at $x = 2$,then the value of $a$ is

  • A
    $-6$
  • B
    $0$
  • C
    $1$
  • D
    $-1$

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