If A = begin{bmatrix} 1 & 3 & 4 2 & 1 & 2 5 | vedclass

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(B) First,we calculate the determinant of matrix $A$:$|A| = 1(1 	imes 1 - 2 	imes 1) - 3(2 	imes 1 - 2 	imes 5) + 4(2 	imes 1 - 1 	imes 5)$$|A|

Vedclass · Accepted Answer

$121$

Vedclass · Answer

(B) First,we calculate the determinant of matrix $A$:$|A| = 1(1 	imes 1 - 2 	imes 1) - 3(2 	imes 1 - 2 	imes 5) + 4(2 	imes 1 - 1 	imes 5)$$|A| = 1(1 - 2) - 3(2 - 10) + 4(2 - 5)$$|A| = 1(-1) - 3(-8) + 4(-3)$$|A| = -1 + 24 - 12 = 11$We know the property $|	ext{adj } A| = |A|^{n-1}$,where $n$ is the order of the matrix.Here,$n = 3$,so $|	ext{adj } A| = |A|^{3-1} = |A|^2$.$|	ext{adj } A| = (11)^2 = 121$.

If $A = \begin{bmatrix} 1 & 3 & 4 \\ 2 & 1 & 2 \\ 5 & 1 & 1 \end{bmatrix}$,then $|\text{adj } A| = $ . . . . . .

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