If A = begin{bmatrix} cos theta & sin theta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The transpose of a matrix $A$,denoted by $A'$,is obtained by interchanging its rows and columns. Given $A = \begin{bmatrix} \cos 	heta & \sin 	h

Vedclass · Accepted Answer

$\begin{bmatrix} \cos 	heta & -\sin 	heta \ \sin 	heta & \cos 	heta \end{bmatrix}$

Vedclass · Answer

(A) The transpose of a matrix $A$,denoted by $A'$,is obtained by interchanging its rows and columns. Given $A = \begin{bmatrix} \cos 	heta & \sin 	heta \ -\sin 	heta & \cos 	heta \end{bmatrix}$. To find $A'$,we swap the elements of the first row with the first column and the second row with the second column. Thus,$A' = \begin{bmatrix} \cos 	heta & -\sin 	heta \ \sin 	heta & \cos 	heta \end{bmatrix}$. Comparing this with the given options,option $A$ is the correct answer.

If $A = \begin{bmatrix} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{bmatrix}$,then $A' = $ . . . . . . .

Similar Questions

If $A = \begin{bmatrix} 3 & x-1 \\ 2x+3 & x+2 \end{bmatrix}$ is a symmetric matrix,then the value of $x$ is

In a skew-symmetric matrix,the diagonal elements are all

Show that the matrix $A = \begin{bmatrix} 0 & 1 & -1 \\ -1 & 0 & 1 \\ 1 & -1 & 0 \end{bmatrix}$ is a skew-symmetric matrix.

Find the transpose of the following matrix: $\left[\begin{array}{c}5 \\ \frac{1}{2} \\ -1\end{array}\right]$.

If $A$ and $B$ are symmetric matrices,prove that $AB - BA$ is a skew-symmetric matrix.

Vedclass Test Series

Exam Paper Generator

Online Exam Module