If begin{bmatrix} 2 & -3 4 & 0 end{bmatrix} | vedclass

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(C) Given the matrix equation: $\begin{bmatrix} 2 & -3 \ 4 & 0 \end{bmatrix} - \begin{bmatrix} a & c \ b & d \end{bmatrix} = \begin{bmatrix} 1 & 4 \

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$(1, 2, -7, 5)$

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(C) Given the matrix equation: $\begin{bmatrix} 2 & -3 \ 4 & 0 \end{bmatrix} - \begin{bmatrix} a & c \ b & d \end{bmatrix} = \begin{bmatrix} 1 & 4 \ 2 & -5 \end{bmatrix}$ Rearranging the terms to solve for the matrix $\begin{bmatrix} a & c \ b & d \end{bmatrix}$: $\begin{bmatrix} a & c \ b & d \end{bmatrix} = \begin{bmatrix} 2 & -3 \ 4 & 0 \end{bmatrix} - \begin{bmatrix} 1 & 4 \ 2 & -5 \end{bmatrix}$ Performing the subtraction element-wise: $a = 2 - 1 = 1$ $c = -3 - 4 = -7$ $b = 4 - 2 = 2$ $d = 0 - (-5) = 5$ Thus,$(a, b, c, d) = (1, 2, -7, 5)$.

If $\begin{bmatrix} 2 & -3 \\ 4 & 0 \end{bmatrix} - \begin{bmatrix} a & c \\ b & d \end{bmatrix} = \begin{bmatrix} 1 & 4 \\ 2 & -5 \end{bmatrix}$,then $(a, b, c, d) = $

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