If vec{a}, vec{b}, vec{c} are position vector | vedclass

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(C) Given the equation $2 \vec{a} + 3 \vec{b} - 5 \vec{c} = \vec{0}$.Rearranging the terms,we get $2 \vec{a} + 3 \vec{b} = 5 \vec{c}$.Dividing by $5$,

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$3:2$ internally

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(C) Given the equation $2 \vec{a} + 3 \vec{b} - 5 \vec{c} = \vec{0}$.Rearranging the terms,we get $2 \vec{a} + 3 \vec{b} = 5 \vec{c}$.Dividing by $5$,we have $\vec{c} = \frac{2 \vec{a} + 3 \vec{b}}{5} = \frac{2 \vec{a} + 3 \vec{b}}{2 + 3}$.This is in the form of the section formula for internal division,$\vec{r} = \frac{m \vec{b} + n \vec{a}}{m + n}$,where the point divides the segment joining $\vec{a}$ and $\vec{b}$ in the ratio $m:n$.Here,$m = 3$ and $n = 2$.Therefore,point $C$ divides the segment $AB$ in the ratio $3:2$ internally.

If $\vec{a}, \vec{b}, \vec{c}$ are position vectors of points $A, B, C$ respectively,with $2 \vec{a}+3 \vec{b}-5 \vec{c}=\vec{0}$,then the ratio in which point $C$ divides segment $AB$ is

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