If $f(x) = \begin{cases} 6 \beta - 3 \alpha x, & \text{if } -4 \leq x < -2 \\ 4x + 1, & \text{if } -2 \leq x \leq 2 \end{cases}$ is continuous on $[-4, 2]$,then $\alpha + \beta = $
- A$\frac{-7}{6}$
- B$\frac{4}{7}$
- C$\frac{-4}{7}$
- D$\frac{7}{6}$
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