If $|8 + z| + |z - 8| = 16$,where $z$ is a complex number,then the point $z$ will lie on

  • A
    $A$ circle
  • B
    $B$ An ellipse
  • C
    $C$ $A$ straight line
  • D
    $D$ None of these

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Let $a, b \in \mathbb{R}$ and $a^2+b^2 \neq 0$. Suppose $S = \{z \in \mathbb{C} : z = \frac{1}{a+ibt}, t \in \mathbb{R}, t \neq 0\}$,where $i = \sqrt{-1}$. If $z = x+iy$ and $z \in S$,then $(x, y)$ lies on:

If $a$ and $c$ are complex numbers and $b$ is a real number in the Argand plane,then the perpendicular distance from $c$ to the line $a \bar{z} + \bar{a} z + b = 0$ is

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