If x=5 sin left(pi t+frac{pi}{3}right) text{ | vedclass

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(A) The general equation for simple harmonic motion is given by $x = A \sin(\omega t + \phi)$.Comparing the given equation $x = 5 \sin \left(\pi t + \

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$5 	ext{ m}, 2 	ext{ s}$

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(A) The general equation for simple harmonic motion is given by $x = A \sin(\omega t + \phi)$.Comparing the given equation $x = 5 \sin \left(\pi t + \frac{\pi}{3}ight) 	ext{ m}$ with the general equation:Amplitude $A = 5 	ext{ m}$.Angular frequency $\omega = \pi 	ext{ rad/s}$.The time period $T$ is related to angular frequency by the formula $T = \frac{2\pi}{\omega}$.Substituting the value of $\omega$: $T = \frac{2\pi}{\pi} = 2 	ext{ s}$.Thus,the amplitude is $5 	ext{ m}$ and the time period is $2 	ext{ s}$.

If $x=5 \sin \left(\pi t+\frac{\pi}{3}\right) \text{ m}$ represents the motion of a particle executing simple harmonic motion,the amplitude and time period of motion,respectively,are

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