If $\frac{9}{(x - 1)(x + 2)^2} = \frac{A}{x - 1} + \frac{B}{x + 2} + \frac{C}{(x + 2)^2}$,then $A - B - C = $

  • A
    $3$
  • B
    $-1$
  • C
    $5$
  • D
    $\text{None of these}$

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