If {V}_{A} and {V}_{B} are the input voltages | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For circuit $(A)$:${V}_{A} = 5\, V \Rightarrow A = 1$,${V}_{A} = 0\, V \Rightarrow A = 0$${V}_{B} = 5\, V \Rightarrow B = 1$,${V}_{B} = 0\, V \Rig

Vedclass · Accepted Answer

$OR$ and $NOT$ Gate

Vedclass · Answer

(B) For circuit $(A)$:${V}_{A} = 5\, V \Rightarrow A = 1$,${V}_{A} = 0\, V \Rightarrow A = 0$${V}_{B} = 5\, V \Rightarrow B = 1$,${V}_{B} = 0\, V \Rightarrow B = 0$If $A = B = 0$,both diodes are reverse biased,so ${V}_{0} = 0\, V$.If $A = 1, B = 0$,diode ${D}_{1}$ is forward biased,so ${V}_{0} = 5\, V$.If $A = 0, B = 1$,diode ${D}_{2}$ is forward biased,so ${V}_{0} = 5\, V$.If $A = 1, B = 1$,both diodes are forward biased,so ${V}_{0} = 5\, V$.This truth table corresponds to an $OR$ gate.For circuit $(B)$:This is a common-emitter $npn$ transistor configuration.When input voltage is $0\, V$ $(A = 0)$,the base-emitter junction is not forward biased,the transistor is in cut-off,and ${V}_{0} = 5\, V$ (logic $1$).When input voltage is $5\, V$ $(A = 1)$,the base-emitter junction is forward biased,the transistor goes into saturation,and ${V}_{0} \approx 0\, V$ (logic $0$).This inversion behavior corresponds to a $NOT$ gate.Therefore,the gates are $OR$ and $NOT$.

If ${V}_{A}$ and ${V}_{B}$ are the input voltages (either $5\, V$ or $0\, V$) and ${V}_{0}$ is the output voltage,then the two gates represented in the following circuit $(A)$ and $(B)$ are:

Similar Questions

Which gate provides the same operation as the circuit shown below?

The output from a $NAND$ gate having inputs $A$ and $B$ given below will be:

Identify the logic operation performed by the given circuit.

If three logic gates are connected as shown in the figure,then the correct truth table of the circuit is

Vedclass Test Series

Exam Paper Generator

Online Exam Module