If n=2 for He^{+} ion,then what is the wavele | vedclass

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(A) For $He^{+}$ ion,the atomic number $Z=2$ and the principal quantum number $n=2$.The circumference of the orbit is given by $2 \pi r = n \lambda$.T

Vedclass · Accepted Answer

$3.33$

Vedclass · Answer

(A) For $He^{+}$ ion,the atomic number $Z=2$ and the principal quantum number $n=2$.The circumference of the orbit is given by $2 \pi r = n \lambda$.The radius of the $n^{th}$ orbit is given by $r = 0.529 \frac{n^{2}}{Z} \ \mathring{A}$.Substituting the value of $r$ in the circumference formula:$2 \pi 	imes (0.529 \frac{n^{2}}{Z}) = n \lambda$$\lambda = \frac{2 \pi 	imes 0.529 	imes n}{Z}$Substituting $n=2$ and $Z=2$:$\lambda = \frac{2 	imes 3.1416 	imes 0.529 	imes 2}{2} \ \mathring{A}$$\lambda = 2 	imes 3.1416 	imes 0.529 \ \mathring{A} \approx 3.33 \ \mathring{A}$.

If $n=2$ for $He^{+}$ ion,then what is the wavelength in $\mathring{A}$?

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