If tan ^{2} theta = sin ^{2} theta + cos ^{2} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given the equation: $	an ^{2} 	heta = \sin ^{2} 	heta + \cos ^{2} 	heta$. We know the fundamental trigonometric identity: $\sin ^{2} 	heta +

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(C) Given the equation: $	an ^{2} 	heta = \sin ^{2} 	heta + \cos ^{2} 	heta$. We know the fundamental trigonometric identity: $\sin ^{2} 	heta + \cos ^{2} 	heta = 1$. Substituting this into the equation,we get: $	an ^{2} 	heta = 1$. Taking the square root on both sides: $	an 	heta = 1$ (considering the acute angle). Since $	an 45^{\circ} = 1$,we have $	heta = 45^{\circ}$.

If $\tan ^{2} \theta = \sin ^{2} \theta + \cos ^{2} \theta$,then $\theta = \ldots$ (in $^{\circ}$)

Similar Questions

$(\sin \theta+\cos \theta)^{2}+(\sin \theta-\cos \theta)^{2} = \dots$

$(1-\cos \theta)(1+\cos \theta) = \dots$

State whether the following is 'True' or 'False' and justify your answer:
If $\cos A + \cos^2 A = 1$,then $\sin^2 A + \sin^4 A = 1$.

$\cot \theta \cdot \tan \theta = \dots$

The value of $\sin^{2} 30^{\circ} - \tan 45^{\circ} + \cos^{2} 60^{\circ} - \cot 90^{\circ}$ is ........

Vedclass Test Series

Exam Paper Generator

Online Exam Module