If $\log _{10} 2986 = 3.4751$,then $\log _{10} 0.02986 =$

  • A
    $\overline{1}.4751$
  • B
    $\overline{2}.4751$
  • C
    $0.34751$
  • D
    None of these

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$\log _{5}\left(1+\frac{1}{5}\right)+\log _{5}\left(1+\frac{1}{6}\right)+\log _{5}\left(1+\frac{1}{7}\right)+\cdots+\log _{5} \left(1+\frac{1}{624}\right)$

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