If sin theta = - frac{1}{sqrt{2}} and tan the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given that $\sin 	heta = - \frac{1}{\sqrt{2}}$ and $	an 	heta = 1$.$1$. The value of $\sin 	heta$ is negative,which implies that $	heta$ must

Vedclass · Accepted Answer

Third

Vedclass · Answer

(C) Given that $\sin 	heta = - \frac{1}{\sqrt{2}}$ and $	an 	heta = 1$.$1$. The value of $\sin 	heta$ is negative,which implies that $	heta$ must lie in either the third or fourth quadrant.$2$. The value of $	an 	heta$ is positive,which implies that $	heta$ must lie in either the first or third quadrant.$3$. For both conditions to be satisfied simultaneously,$	heta$ must lie in the third quadrant,where both $\sin 	heta$ is negative and $	an 	heta$ is positive.Therefore,$	heta$ lies in the third quadrant.

If $\sin \theta = - \frac{1}{\sqrt{2}}$ and $\tan \theta = 1$,then $\theta$ lies in which quadrant?

Similar Questions

The value of $\frac{\tan 70^\circ - \tan 20^\circ}{\tan 50^\circ} = $

$\sqrt{\frac{1+\cos \theta}{1-\cos \theta}}+\sqrt{\frac{1-\cos \theta}{1+\cos \theta}}=$

The value of $\sin^2 5^\circ + \sin^2 10^\circ + \sin^2 15^\circ + \dots + \sin^2 85^\circ + \sin^2 90^\circ$ is equal to

If $\sin x + \cos x = \frac{1}{5},$ then $\tan 2x$ is

$\sqrt {\frac{{1 - \sin A}}{{1 + \sin A}}} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module