If $\sin \theta + \cos \theta = 1$,then $\sin \theta \cos \theta = $

  • A
    $0$
  • B
    $1$
  • C
    $2$
  • D
    $0.5$

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If $\tan \theta = t,$ then $\tan 2\theta + \sec 2\theta = $

$\sqrt{\frac{1+\cos \theta}{1-\cos \theta}}+\sqrt{\frac{1-\cos \theta}{1+\cos \theta}}=$

$\tan \theta \sin \left( \frac{\pi }{2} + \theta \right) \cos \left( \frac{\pi }{2} - \theta \right) = $

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