If sin theta + csc theta = 2,then sin^2 theta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given that $\sin 	heta + \csc 	heta = 2$.Squaring both sides of the equation:$(\sin 	heta + \csc 	heta)^2 = 2^2$$\sin^2 	heta + \csc^2 	heta

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) Given that $\sin 	heta + \csc 	heta = 2$.Squaring both sides of the equation:$(\sin 	heta + \csc 	heta)^2 = 2^2$$\sin^2 	heta + \csc^2 	heta + 2 \sin 	heta \csc 	heta = 4$Since $\csc 	heta = \frac{1}{\sin 	heta}$,we have $\sin 	heta \csc 	heta = 1$.Substituting this value into the equation:$\sin^2 	heta + \csc^2 	heta + 2(1) = 4$$\sin^2 	heta + \csc^2 	heta + 2 = 4$$\sin^2 	heta + \csc^2 	heta = 4 - 2 = 2$.

If $\sin \theta + \csc \theta = 2$,then $\sin^2 \theta + \csc^2 \theta = $

Similar Questions

Given that $\pi < \alpha < \frac{3\pi}{2},$ then the expression $\sqrt{4\sin^4 \alpha + \sin^2 2\alpha} + 4\cos^2 \left( \frac{\pi}{4} - \frac{\alpha}{2} \right)$ is equal to

If $x + \frac{1}{x} = 2\cos \alpha$, then ${x^n} + \frac{1}{{{x^n}}} = $

If $\tan B = \frac{n \sin A \cos A}{1 - n \cos^2 A}$,then $\tan(A + B)$ equals

If $x \sin 45^\circ \cos^2 60^\circ = \frac{\tan^2 60^\circ \csc 30^\circ}{\sec 45^\circ \cot^2 30^\circ}$,then $x = $

The value of $\sin ^{2} 75^{\circ}-\sin ^{2} 15^{\circ}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module