If sqrt{5} = 2.236,then the value of frac{sqr | vedclass

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(B) Given expression: $\frac{\sqrt{5}}{2} - \frac{10}{\sqrt{5}} + \sqrt{125}$Simplify each term:$1$. $\frac{10}{\sqrt{5}} = \frac{10 	imes \sqrt{5}}{

Vedclass · Accepted Answer

$7.826$

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(B) Given expression: $\frac{\sqrt{5}}{2} - \frac{10}{\sqrt{5}} + \sqrt{125}$Simplify each term:$1$. $\frac{10}{\sqrt{5}} = \frac{10 	imes \sqrt{5}}{5} = 2\sqrt{5}$$2$. $\sqrt{125} = \sqrt{25 	imes 5} = 5\sqrt{5}$Substitute these into the expression:$\frac{\sqrt{5}}{2} - 2\sqrt{5} + 5\sqrt{5} = \frac{\sqrt{5}}{2} + 3\sqrt{5} = \sqrt{5} \left( \frac{1}{2} + 3 ight) = \frac{7}{2} \sqrt{5}$Given $\sqrt{5} = 2.236$,substitute the value:$\frac{7}{2} 	imes 2.236 = 7 	imes 1.118 = 7.826$

If $\sqrt{5} = 2.236$,then the value of $\frac{\sqrt{5}}{2} - \frac{10}{\sqrt{5}} + \sqrt{125}$ is:

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