(A) Given expression: $p(p^{2} + 3p + 3) = p^{3} + 3p^{2} + 3p$.To simplify this,we can add and subtract $1$ to complete the cube formula: $(p+1)^{3}

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(A) Given expression: $p(p^{2} + 3p + 3) = p^{3} + 3p^{2} + 3p$.To simplify this,we can add and subtract $1$ to complete the cube formula: $(p+1)^{3} = p^{3} + 3p^{2} + 3p + 1$.Therefore,$p^{3} + 3p^{2} + 3p = (p+1)^{3} - 1$.Substitute $p = 99$ into the expression:$(99 + 1)^{3} - 1 = 100^{3} - 1$.$100^{3} = 1000000$.$1000000 - 1 = 999999$.

Competitive Quantitative Aptitude Number system Simplification

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If $p = 99$,then the value of $p(p^{2} + 3p + 3)$ is:

A
$999999$
B
$988899$
C
$989898$
D
$998889$

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If $p = 99$,then the value of $p(p^{2} + 3p + 3)$ is:

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$\left(\frac{10.3 \times 10.3 \times 10.3 + 1}{10.3 \times 10.3 - 10.3 + 1}\right)$ is equal to (in $.3$)

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