If sqrt{3} = 1.732,then the value of frac{9 + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given expression: $\frac{9 + 2\sqrt{3}}{\sqrt{3}}$Divide each term in the numerator by the denominator:$= \frac{9}{\sqrt{3}} + \frac{2\sqrt{3}}{\s

Vedclass · Accepted Answer

$7.196$

Vedclass · Answer

(B) Given expression: $\frac{9 + 2\sqrt{3}}{\sqrt{3}}$Divide each term in the numerator by the denominator:$= \frac{9}{\sqrt{3}} + \frac{2\sqrt{3}}{\sqrt{3}}$$= \frac{9}{\sqrt{3}} + 2$Rationalize the first term:$= \frac{9 	imes \sqrt{3}}{\sqrt{3} 	imes \sqrt{3}} + 2 = \frac{9\sqrt{3}}{3} + 2 = 3\sqrt{3} + 2$Substitute the value of $\sqrt{3} = 1.732$:$= 3(1.732) + 2$$= 5.196 + 2$$= 7.196$

If $\sqrt{3} = 1.732$,then the value of $\frac{9 + 2\sqrt{3}}{\sqrt{3}}$ is

Similar Questions

If $6088 \times ? = 7610$,then the value of $?$ is

The simplification of $\left[\frac{1}{2}+\frac{1}{2}\left\{\frac{3}{4}-\frac{1}{2}\left(\frac{7}{8}-\frac{3}{4}\right)\right\}\right]$ yields

If $5 \sqrt{5} \times 5^{3} \div 5^{-\frac{3}{2}} = 5^{a+2},$ then the value of $a$ is

$7 \frac{11}{18} + 13 \frac{1}{9} + 5 \frac{7}{9} - 16 \frac{2}{3} = ?$

Which one of the following is the smallest fraction?
$\frac{6}{11}, \frac{13}{17}, \frac{19}{27}, \frac{21}{23}, \frac{5}{7}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module