If frac{a^{2}+b^{2}}{c^{2}+d^{2}}=frac{a b}{c | vedclass

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(D) Given: $\frac{a^{2}+b^{2}}{c^{2}+d^{2}}=\frac{a b}{c d}$Multiply both sides by $2$: $\frac{a^{2}+b^{2}}{c^{2}+d^{2}}=\frac{2 a b}{2 c d}$Applying

Vedclass · Accepted Answer

$\frac{c+d}{c-d}$

Vedclass · Answer

(D) Given: $\frac{a^{2}+b^{2}}{c^{2}+d^{2}}=\frac{a b}{c d}$Multiply both sides by $2$: $\frac{a^{2}+b^{2}}{c^{2}+d^{2}}=\frac{2 a b}{2 c d}$Applying Componendo and Dividendo: $\frac{a^{2}+b^{2}+2 a b}{a^{2}+b^{2}-2 a b}=\frac{c^{2}+d^{2}+2 c d}{c^{2}+d^{2}-2 c d}$This simplifies to: $\frac{(a+b)^{2}}{(a-b)^{2}}=\frac{(c+d)^{2}}{(c-d)^{2}}$Taking the square root on both sides: $\frac{a+b}{a-b}=\frac{c+d}{c-d}$

If $\frac{a^{2}+b^{2}}{c^{2}+d^{2}}=\frac{a b}{c d},$ then find the value of $\frac{a+b}{a-b}$ in terms of $c$ and $d$ only.

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