If frac{a}{b} = frac{1}{2}, then frac{3a + 2b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(NONE) Given that $\frac{a}{b} = \frac{1}{2}.$
To find the value of $\frac{3a + 2b}{3a - 2b},$ divide both the numerator and the denominator by $b$:

Vedclass · Accepted Answer

$-7$

Vedclass · Answer

(NONE) Given that $\frac{a}{b} = \frac{1}{2}.$
To find the value of $\frac{3a + 2b}{3a - 2b},$ divide both the numerator and the denominator by $b$:
$\frac{3a + 2b}{3a - 2b} = \frac{3(\frac{a}{b}) + 2}{3(\frac{a}{b}) - 2}.$
Substitute $\frac{a}{b} = \frac{1}{2}$ into the expression:
$= \frac{3(\frac{1}{2}) + 2}{3(\frac{1}{2}) - 2} = \frac{\frac{3}{2} + 2}{\frac{3}{2} - 2}.$
$= \frac{\frac{3 + 4}{2}}{\frac{3 - 4}{2}} = \frac{\frac{7}{2}}{-\frac{1}{2}}.$
$= \frac{7}{2} 	imes (-\frac{2}{1}) = -7.$

If $\frac{a}{b} = \frac{1}{2},$ then $\frac{3a + 2b}{3a - 2b}$ is equal to

Similar Questions

If $x = \frac{4 \sqrt{ab}}{\sqrt{a} + \sqrt{b}}$,then what is the value of $\frac{x + 2 \sqrt{a}}{x - 2 \sqrt{a}} + \frac{x + 2 \sqrt{b}}{x - 2 \sqrt{b}}$ (when $a \neq b$)?

If $a^{2}+b^{2}+\frac{1}{a^{2}}+\frac{1}{b^{2}}=4,$ then the value of $a^{2}+b^{2}$ will be

If $\frac{x-a^{2}}{b+c}+\frac{x-b^{2}}{c+a}+\frac{x-c^{2}}{a+b}=4(a+b+c),$ then $x$ is equal to:

If $\frac{a}{a+b}=\frac{17}{23},$ what is $\frac{a+b}{a-b}$ equal to?

If $x - (1/x) = \sqrt{13}$,then what is the value of $x^5 - (1/x^5)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module