If 3x + 7 = x^2 + P = 7x + 5,what is the valu | vedclass

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(B) Given the equation $3x + 7 = x^2 + P = 7x + 5$.First,equate the two expressions involving $x$: $3x + 7 = 7x + 5$.Rearranging the terms,we get $7x

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$8 \frac{1}{4}$

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(B) Given the equation $3x + 7 = x^2 + P = 7x + 5$.First,equate the two expressions involving $x$: $3x + 7 = 7x + 5$.Rearranging the terms,we get $7x - 3x = 7 - 5$,which simplifies to $4x = 2$.Thus,$x = 2/4 = 1/2$.Now,substitute $x = 1/2$ into the first expression: $3(1/2) + 7 = 1.5 + 7 = 8.5$ or $17/2$.Since $x^2 + P = 17/2$,substitute $x = 1/2$ into this equation:$(1/2)^2 + P = 17/2$.$1/4 + P = 17/2$.$P = 17/2 - 1/4 = 34/4 - 1/4 = 33/4$.Converting to a mixed fraction,$P = 8 \frac{1}{4}$.

If $3x + 7 = x^2 + P = 7x + 5$,what is the value of $P$?

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