જો $x = \frac{a}{a-1}$ અને $y = \frac{1}{a-1}$ હોય,તો

$\frac{3}{4} \left(1+\frac{1}{3}\right) \left(1+\frac{2}{3}\right) \left(1-\frac{2}{5}\right) \left(1+\frac{6}{7}\right) \left(1-\frac{12}{13}\right)$ ની કિંમત શોધો.

$3 . \overline{87} - 2 . \overline{59} = ?$

$13 \frac{4}{?} + 5 \frac{3}{4} \text{ of } 3 \frac{1}{5} \div 4 \frac{3}{5} = 17 \frac{4}{5}$

$\frac{2 \frac{1}{3}-1 \frac{2}{11}}{3+\frac{1}{3+\frac{1}{3+\frac{1}{3}}}}$ ની કિંમત શોધો.

$\frac{1}{3} + \frac{1}{2} + \frac{1}{x} = 4$. તો $x = ?$