If 1 is added to the denominator of a fractio | vedclass

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(C) Let the required fraction be $\frac{x}{y}$.According to the first condition,adding $1$ to the denominator gives $\frac{x}{y+1} = \frac{1}{2}$.This

Vedclass · Accepted Answer

$\frac{2}{3}$

Vedclass · Answer

(C) Let the required fraction be $\frac{x}{y}$.According to the first condition,adding $1$ to the denominator gives $\frac{x}{y+1} = \frac{1}{2}$.This simplifies to $2x = y + 1$,or $2x - y = 1$ (Equation $1$).According to the second condition,adding $1$ to the numerator gives $\frac{x+1}{y} = 1$.This simplifies to $x + 1 = y$,or $x - y = -1$ (Equation $2$).Subtracting Equation $2$ from Equation $1$:$(2x - y) - (x - y) = 1 - (-1)$$2x - y - x + y = 1 + 1$$x = 2$.Substituting $x = 2$ into Equation $2$:$2 - y = -1$$y = 3$.Therefore,the fraction is $\frac{2}{3}$.

If $1$ is added to the denominator of a fraction,the fraction becomes $\frac{1}{2}$. If $1$ is added to the numerator,the fraction becomes $1$. The fraction is

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