If 6 A = 4 B = 9 C,what is A : B : C? | vedclass

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(D) Given the equation $6 A = 4 B = 9 C = k$,where $k$ is a constant.Then,$A = \frac{k}{6}$,$B = \frac{k}{4}$,and $C = \frac{k}{9}$.Therefore,the rati

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$6 : 9 : 4$

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(D) Given the equation $6 A = 4 B = 9 C = k$,where $k$ is a constant.Then,$A = \frac{k}{6}$,$B = \frac{k}{4}$,and $C = \frac{k}{9}$.Therefore,the ratio $A : B : C = \frac{k}{6} : \frac{k}{4} : \frac{k}{9}$.Dividing by $k$,we get $A : B : C = \frac{1}{6} : \frac{1}{4} : \frac{1}{9}$.To simplify the ratio,multiply each term by the least common multiple $(LCM)$ of $6, 4,$ and $9$,which is $36$.$A : B : C = (\frac{1}{6} 	imes 36) : (\frac{1}{4} 	imes 36) : (\frac{1}{9} 	imes 36)$.$A : B : C = 6 : 9 : 4$.

If $6 A = 4 B = 9 C$,what is $A : B : C$?

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