If 50 fewer candidates had applied and 25 few | vedclass

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(C) Let the number of selected candidates be $2x$ and the number of unselected candidates be $x$.Total candidates applied = $2x + x = 3x$.According to

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$375$

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(C) Let the number of selected candidates be $2x$ and the number of unselected candidates be $x$.Total candidates applied = $2x + x = 3x$.According to the problem,if $50$ fewer candidates applied,the new total is $3x - 50$.If $25$ fewer were selected,the new number of selected candidates is $2x - 25$.The new number of unselected candidates is $(3x - 50) - (2x - 25) = x - 25$.The ratio of selected to unselected is given as $9:4$,so:$\frac{2x - 25}{x - 25} = \frac{9}{4}$$4(2x - 25) = 9(x - 25)$$8x - 100 = 9x - 225$$x = 125$.The total number of candidates who applied is $3x = 3 	imes 125 = 375$.

If $50$ fewer candidates had applied and $25$ fewer had been selected,the ratio of selected to unselected candidates would have been $9:4$. How many candidates had applied if the initial ratio of selected to unselected candidates was $2:1$?

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