If 4x + i(3x - y) = 3 + i(-6),where x and y a | vedclass

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(A) Given the equation: $4x + i(3x - y) = 3 + i(-6)$.Equating the real and imaginary parts on both sides,we get:Real part: $4x = 3 \implies x = \frac{

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$x = \frac{3}{4}, y = \frac{33}{4}$

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(A) Given the equation: $4x + i(3x - y) = 3 + i(-6)$.Equating the real and imaginary parts on both sides,we get:Real part: $4x = 3 \implies x = \frac{3}{4}$.Imaginary part: $3x - y = -6$.Substitute $x = \frac{3}{4}$ into the imaginary part equation:$3(\frac{3}{4}) - y = -6$$\frac{9}{4} - y = -6$$y = \frac{9}{4} + 6$$y = \frac{9 + 24}{4} = \frac{33}{4}$.Thus,$x = \frac{3}{4}$ and $y = \frac{33}{4}$.

If $4x + i(3x - y) = 3 + i(-6)$,where $x$ and $y$ are real numbers,then find the values of $x$ and $y$.

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