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(C) We have $2A - B = 2 \begin{bmatrix} 1 & 2 & 3 \ 2 & 3 & 1 \end{bmatrix} - \begin{bmatrix} 3 & -1 & 3 \ -1 & 0 & 2 \end{bmatrix}$.First,multiply

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$\begin{bmatrix} -1 & 5 & 3 \ 5 & 6 & 0 \end{bmatrix}$

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(C) We have $2A - B = 2 \begin{bmatrix} 1 & 2 & 3 \ 2 & 3 & 1 \end{bmatrix} - \begin{bmatrix} 3 & -1 & 3 \ -1 & 0 & 2 \end{bmatrix}$.First,multiply matrix $A$ by the scalar $2$:$2A = \begin{bmatrix} 2(1) & 2(2) & 2(3) \ 2(2) & 2(3) & 2(1) \end{bmatrix} = \begin{bmatrix} 2 & 4 & 6 \ 4 & 6 & 2 \end{bmatrix}$.Now,subtract matrix $B$ from $2A$:$2A - B = \begin{bmatrix} 2 & 4 & 6 \ 4 & 6 & 2 \end{bmatrix} - \begin{bmatrix} 3 & -1 & 3 \ -1 & 0 & 2 \end{bmatrix}$.Perform element-wise subtraction:$2A - B = \begin{bmatrix} 2 - 3 & 4 - (-1) & 6 - 3 \ 4 - (-1) & 6 - 0 & 2 - 2 \end{bmatrix} = \begin{bmatrix} -1 & 5 & 3 \ 5 & 6 & 0 \end{bmatrix}$.

If $A = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 3 & 1 \end{bmatrix}$ and $B = \begin{bmatrix} 3 & -1 & 3 \\ -1 & 0 & 2 \end{bmatrix}$,then find $2A - B$.

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