If A = begin{bmatrix} 1 & 1 & -2 2 & 1 & -3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given the matrix $A = \begin{bmatrix} 1 & 1 & -2 \ 2 & 1 & -3 \ 5 & 4 & -9 \end{bmatrix}$.To find the determinant $|A|$,we expand along the firs

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(C) Given the matrix $A = \begin{bmatrix} 1 & 1 & -2 \ 2 & 1 & -3 \ 5 & 4 & -9 \end{bmatrix}$.To find the determinant $|A|$,we expand along the first row:$|A| = 1 \begin{vmatrix} 1 & -3 \ 4 & -9 \end{vmatrix} - 1 \begin{vmatrix} 2 & -3 \ 5 & -9 \end{vmatrix} + (-2) \begin{vmatrix} 2 & 1 \ 5 & 4 \end{vmatrix}$Calculating the $2 	imes 2$ determinants:$|A| = 1((1)(-9) - (-3)(4)) - 1((2)(-9) - (-3)(5)) - 2((2)(4) - (1)(5))$$|A| = 1(-9 + 12) - 1(-18 + 15) - 2(8 - 5)$$|A| = 1(3) - 1(-3) - 2(3)$$|A| = 3 + 3 - 6$$|A| = 6 - 6 = 0$Thus,the value of $|A|$ is $0$.

If $A = \begin{bmatrix} 1 & 1 & -2 \\ 2 & 1 & -3 \\ 5 & 4 & -9 \end{bmatrix}$,find $|A|$.

Similar Questions

If $\left| \begin{array}{ccc} 6i & -3i & 1 \\ 4 & 3i & -1 \\ 20 & 3 & i \end{array} \right| = x + iy$,then $(x, y)$ is

The value of $\left|\begin{array}{lll}(a+1)(a+2) & a+2 & 1 \\ (a+2)(a+3) & a+3 & 1 \\ (a+3)(a+4) & a+4 & 1\end{array}\right|$ is

The area of the triangle whose vertices are $(3,5), (2,2)$ and $(k, 2)$ is $3$ sq. unit. Then,the value of $k$ is . . . . . . .

In order that the matrix $\begin{bmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 3 & \lambda & 5 \end{bmatrix}$ be non-singular,$\lambda$ should not be equal to:

If $A$ and $B$ are square matrices of order $3$ such that $|A| = -1$ and $|B| = 3$,then find the value of $|3AB|$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module