If Delta H is the change in enthalpy and Delt | vedclass

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(D) The relationship between enthalpy change and internal energy change for a gaseous reaction is given by the equation: $\Delta H = \Delta E + \Delta

Vedclass · Accepted Answer

$\Delta H < \Delta E$ only if the number of moles of the products is less than the number of moles of the reactants

Vedclass · Answer

(D) The relationship between enthalpy change and internal energy change for a gaseous reaction is given by the equation: $\Delta H = \Delta E + \Delta n_g RT$. Here,$\Delta n_g$ is the change in the number of moles of gaseous products and reactants,defined as $\Delta n_g = n_p - n_r$. If the number of moles of products is less than the number of moles of reactants,then $\Delta n_g$ is negative $(\Delta n_g In this case,$\Delta H = \Delta E - |\Delta n_g| RT$,which implies $\Delta H Therefore,the correct option is $D$.

If $\Delta H$ is the change in enthalpy and $\Delta E$ is the change in internal energy accompanying a gaseous reaction,which of the following is true?

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