The graph shows the variation of Ionization P | vedclass

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(A) In a group,the Ionization Potential $(I.P.)$ generally decreases from top to bottom due to an increase in atomic size and shielding effect.However

Vedclass · Accepted Answer

$13$ group

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(A) In a group,the Ionization Potential $(I.P.)$ generally decreases from top to bottom due to an increase in atomic size and shielding effect.However,the graph shows an irregular trend $(A > B  D This specific zig-zag pattern of $I.P.$ values is characteristic of elements in group $13$ (e.g.,$B, Al, Ga, In, Tl$).In group $13$,the $I.P.$ decreases from $B$ to $Al$,then increases from $Al$ to $Ga$ due to poor shielding of $d$-electrons,decreases from $Ga$ to $In$,and increases from $In$ to $Tl$ due to poor shielding of $f$-electrons.Therefore,the group is $13$.

The graph shows the variation of Ionization Potential $(I.P.)$ with Atomic Number $(At. No.)$ for elements $A$ to $E$. If these elements belong to the same group in the periodic table,identify the group.

Similar Questions

Observe the following statements.
Statement $(A)$: In general,the ionisation potential value decreases on moving down in the group.
Statement $(B)$: The $1$st ionisation potential of sodium is greater than that of potassium.
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The electronic configurations of elements $A, B$ and $C$ are $[He] 2s^1$,$[Ne] 3s^1$ and $[Ar] 4s^1$ respectively. Which one of the following orders is correct for the first ionization potentials (in $kJ \ mol^{-1}$) of $A, B$ and $C$?

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