If EAN of central metal cation M^{2+} in a no | vedclass

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(C) The $EAN$ (Effective Atomic Number) rule is given by the formula: $EAN = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number})$.Given

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$6$

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(C) The $EAN$ (Effective Atomic Number) rule is given by the formula: $EAN = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number})$.Given:$EAN = 36$$Z = 26$Oxidation state of $M^{2+} = +2$Let the coordination number be $CN$.Substituting the values:$36 = 26 - 2 + 2 	imes (CN)$$36 = 24 + 2 	imes (CN)$$12 = 2 	imes (CN)$$CN = 6$.Since the ligand is monodentate,the number of ligands is equal to the coordination number,which is $6$.

If $EAN$ of central metal cation $M^{2+}$ in a non-chelating complex is $36$ and atomic number of metal $M$ is $26$,then the number of monodentate ligands in this complex is:

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