If $\alpha = 0.98$ and the current through the emitter $i_e = 20 \, mA$,the value of $\beta$ is

In case of a bipolar transistor,$\beta = 45$. The potential drop across the collector resistance of $1 \ k\Omega$ is $5 \ V$. The base current is approximately: (in $\mu A$)

The voltage gain of a transistor in common emitter configuration is $160$. The resistances in base and collector sides of the circuit are $1 \text{ k}\Omega$ and $4 \text{ k}\Omega$ respectively. If the change in base current is $100 \mu A$, then the change in output current is:

If the resistance $R_1$ is increased (see figure), how will the readings of the ammeter and voltmeter change?

In the circuit shown in the figure,the input voltage $V_i$ is $20\, V$,$V_{BE} = 0$,and $V_{CE} = 0$. The values of $I_B$,$I_C$,and $\beta$ are given by:

Three circuit connections of a $PNP$ transistor are given below. Which of the following represents the Common-Emitter configuration?