If $f\left( x \right) = {\log _e}\,\left( {\frac{{1 - x}}{{1 + x}}} \right)$, $\left| x \right| < 1$, then $f\left( {\frac{{2x}}{{1 + {x^2}}}} \right)$ is equal to

  • [JEE MAIN 2019]
  • A

    $2f\left( x \right)$

  • B

    ${\left( {f\left( x \right)} \right)^2}$

  • C

    $2f\left( x^2 \right)$

  • D

    $ - 2f\left( x \right)$

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  • [JEE MAIN 2021]

If the domain of the function $f(x)=\sin ^{-1}\left(\frac{x-1}{2 x+3}\right)$ is $R-(\alpha, \beta)$ then $12 \alpha \beta$ is equal to :

  • [JEE MAIN 2024]

Which of the following function is surjective but not injective

Product of all the solution of the equation  ${x^{1 + {{\log }_{10}}x}} = 100000x$ is

Let $f(x) = {\cos ^{ - 1}}\left( {\frac{{2x}}{{1 + {x^2}}}} \right) + {\sin ^{ - 1}}\left( {\frac{{1 - {x^2}}}{{1 + {x^2}}}} \right)$ then the value of $f(1) + f(2)$, is -